Tuesday, May 02, 2006

The second-round matchups

East: Ottawa (1), Carolina (2), New Jersey (3), Buffalo (4)
West: San Jose (5), Colorado (7), Edmonton (8)

Which means...
Ottawa will play Buffalo

New Jersey will play Carolina

San Jose will play
- if Calgary wins, Colorado; if Anaheim wins, Edmonton

Colorado will play
- if Calgary wins, San Jose; if Anaheim wins, Anaheim

Edmonton will play
- if Calgary wins, Calgary; if Anaheim wins, San Jose

The really interesting thing in the West is that one of the scenarios involves all four lower-seeded teams winning through, which would mean San Jose, then the top-seeded team, would face the Oilers. Anaheim would be the second-highest Western Conference team remaining and play Colorado. Zany stuff.


At 3:29 p.m., May 02, 2006, Blogger Black Dog Hates Skunks said...

That is indeed quite zany, James.

Hey newspaper man - can you bring the full resources available at your disposal (ask the Hat) if there has ever been a playoff year where the top four seeds were eliminated in the first round. I would say no but my memory isn't what it used to be.

Enjoy this blog btw.

At 4:35 p.m., May 02, 2006, Blogger James Mirtle said...

Since the league went to a 1 vs. 8 format in 1993-94, it's never happened.

I don't know about before that, as there was as system where teams played within their own divisions in the first round.

At 9:55 p.m., May 02, 2006, Anonymous Anonymous said...

Meanwhile, the East is all set, with the top 4 going through.


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