Columbus: The biggest loser
ESPN's Page 2 has a fascinating list up of which professional sports cities have had the highest combined losing percentage of all their franchises.
The winner (or loser, as it were)? Columbus, Ohio, where the Blue Jackets and a long-defunct NFL franchise combined for a .653 losing percentage.
Here's a look at how NHL cities, past and present, ranked among the 50 in the survey:
1. Columbus
2. Tampa
3. Vancouver
5. San Jose
9. Washington
10. Kansas City
11. Ottawa
12. Nashville
15. Denver
16. Philadelphia
18. Anaheim
19. Minneapolis/St. Paul
20. Miami
21. Raleigh
22. Oakland
23. Toronto
24. St. Louis
26. Atlanta
30. Cleveland
31. Chicago
32. Pittsburgh
34. Detroit
35. Buffalo
37. Dallas
38. Boston
40. Phoenix
41. New York/New Jersey
42. Los Angeles
45. Calgary
46. Montreal
47. Edmonton
Labels: Blue Jackets
by James Mirtle @ 5:03 PM
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8 Comments:
18. Anaheim
19. Minneapolis/St. Paul
Ooh, the plot thickens...
Curious that they count the ABA but not the WHA .... I forgot to check if they counted the 70's WFL or the 80's USFL.
Any list of losing teams that doesn't include the Winnipeg Jets doesn't count. Oh, my beloved Jets, how you lost.
Before we cry any tears for Columbus I think it's worth mentioning that it's the home of "The" Ohio State University, and the last time I checked they had a pretty good football team.
1992-93 skewed the record for San Jose. An 11-61-2 record will do that for a team.
Nice of them to include the 2-time champion SJ Earthquakes. I guess the MLS is not even on their radar.
A pretty good football team but not quite the best. That NC performance probably stung a bit.
Apparently the Montreal Wanderers and their whole six games don't count.
Ohio State's not a pro team?
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